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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Balance by oxidation number method...............
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sneha (1460)

Olaaa!! Perrrfect answer. 236  [376 rates]

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The answer is

10FeSO4 +2KMnO4 +8H2SO4 -----------> 5Fe2(SO4)3 +K2SO4  + 2MnSO4 +8H2O

step 1

Fe+2 -------> Fe+3 + e          ...(1)   

Mn+7 + 5e -----> Mn+2        ...(2)

Now,

5  (1) + (2)

5Fe+2  + Mn+7-------> 5Fe+3 + Mn+2

or,

FeSO4 + KMnO4  -----------> 5/2Fe2(SO4)3 +MnSO4

balancing for sulphate ions and oxygen, we get the final equation.


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