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Chemical Kinetics
Tags: Engineering Entrance  |  IIT JEE  |  Physical Chemistry
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Physical Chemistry V & P Chapters

* Molecularity of rxn :- No. of atom , ions or molcularity that must collide with one another simultaneous to result into chemical rxn.

eg. 2NO2 + O2 2NO2

Molecularity = 2 +1 = 3 Note :- Molecularity is defined for elementary rxn. not for complex.

Complex rxn. takes place in sequence of step & slowest step is c/d rate determining step.

Molecularity is always whole no. & or due may be traction.

A series of step rxn. account for over all rxn. c/d mechanism of rxn.

eg. 2N2O5 4NO2 + O2

Rate = K[N2O5]


Step 1:- N2O5 NO2 + NO3

Step 2:- N2O5 3NO2 + O2

(1) Rxns involving two Ist order consecutive ateps:-

Step 1:- R X

Step 2:- X P





Illustration :- 2NO(I) + O2/sub>(I) 2NO2 (I)



Predict rate law, if mechanism is

2NO2 + O2 NO3(Fast)


NO3 NO NO2 + NO2 (Slow)



Ans :- From Slow Step:- Rate = K1 [NO3][NO2] ................................ (1)

From Fast Step:- eqm. const. K =

Substituting value of [NO3] from (11) in (1), we get


Rate = K'[NO]2[O2]


Integrating Rate expression for zero order rxn A P dts

Rate = = K[A]0 = K

d[A] = - K dt

[A] = - kt + C ............................................ (1)

C = [A]0

Substituting value of C in eq. (1)

[A] = - Kt + [A]0 ................................................. (11)






Half life:- It time is which half of substitution has reacted.









Illustration:- Rate of decomposition of NH3 on platenium surface is zero order. What is rate of production on of N2 ?



Rate =

For zero order rxn = K



A Products

After time t

Rate rxn



At t = 0, x = 0,

- ln a = C .................................................. (111)

Putting value of C in eq. (11)

- ln (a - x) = Kt + (- ln a)

Kt = ln



Putting a = [A]0 & (a - x) = [A]







Half life :-

Dumb question:- What is the difference between and order?

Soln:- Moleularity is a theoretical concept while order is determined using experiments. Moleularity is always a whole number & it cannot be zero while order can take any positive value and zero also.


Question:-


K = 6.2 X 10-4S-1

Calculaten rate when [N2O5] = 1.25 mol/L

Ans:- Rate = K[N2O5]

= 6.2 X 10-4 [1.25] = 7.75 X 10-4 mol-1LS-1


Integrated law for IInd order :-

B + RA Products



Rate (a - x)(b - x)





At t = 0, x = 0



Putting in (1) the value of C



Half Life Period:-

order of rxn.

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