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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Circular Motion
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[Post New] 24 May 2007 15:17:35 IST
   Subject: Re:Circular Motion
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HEMANT BHARDWAJ (806)

Olaaa!! Perrrfect answer. 146  [184 rates]
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Q- 28
force in outward direction=m*r*2

force along inclined plane=m*r*2cos

aceleration along inclined plane "a"=r*2cos

use second eq of motion

initial velocity u=0

distance travell=L

L=0*t+1/2 * a * t2

put value of a

t=  2L/rcos *2
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  this reply:   5 points  (with 1  Olaaa!! Perrrfect answer.   in 1   votes   )     [?]
 
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