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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: 145 acceleration...............
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HEMANT BHARDWAJ (806)

Olaaa!! Perrrfect answer. 146  [184 rates]

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since force exerted= change in momentum of water i.e


F=dP/dt


P=MV


here velocity is constant hence force exerted by water=V*dM/dt


dM/dt=1kg/sec


v=5m/sec


hence F=5N


so acceleration=F/M=5/2=2.5m/s2


 


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  this reply:   5 points  (with Olaaa!! Perrrfect answer.   in 1   votes   )     [?]
 
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