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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: domain of 2^x+2^y=2
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HIMANSHU JAIN (376)

Olaaa!! Perrrfect answer. 62  [95 rates]

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2^y = 2 - 2^x
taking log:
ylog2 = log (2-2^x)

y = log (2-2^x)  with base 2.

Now, properties for log t  are:

1)t>0

2) base should be positive and not equal to 1. (which is 2 in our case)

 

So, 2-2^x >0

=> 2 > 2^x

=> x<1. (domain)

 


Himanshu Jain P.E.C. http://jainhim.blogspot.com/
  this reply:   10 points  (with Olaaa!! Perrrfect answer.   in 2   votes   )     [?]
 
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