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Answer d).. Draw proper dia and resolve force F into two components Fsin@ will cancel each other and Fcos@ will add ............. where @ is angle which forces make with y-axis. so net force toward the origin is 2Fcos@=-(2kqQ/x*x)*cos@.......... (where cos@=y/x) so Net force the origin is = -2kqQy/x*x*x here y ivary b/w -2a to 2a. so answer is (d) but if y is very small as compare to a then it will execute SHM
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