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hey can anyone plz rate the book L G WADE Jr. i found it good for organic concepts
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you mean physics galaxy?
i too solve h c v
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hey anyone how would you rate D C Pandey's Mechanics i was able to solve many questions after reading the conceptual points that he has given in the chapters
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the body must be placed on an inclined plane(shd be that as you cannot take a plane surface)
and if the body is not accelarating down the incline then mgsin(theta)= (mu)x normal force
normal force =mg cos(theta)
mg sin(theta)=(mu)mgcos(theta)
mg cancels on both sides
tan (theta)= (mu)
(mu) is the coefficient of frictional force
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for the first question, the momentum is conserved along the direction perpendicular to the surface( which is horizontal) so initial momentum perpendicular to surface is mvcos(theta)
final momentum is -mvcos(theta)
change in momentum is mvcos(theta)-(-mvcos(theta))=2mvcos(theta)
for the second one force on particle= d(K)/ds= 2as
plz rate me
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1 1 36 can also be an answer right?
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plz rate me if the ans is right
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since the product 36 can be split as 1x2x2x3x3 hence the possibilities are 2,3,6 /2,9,2/ 3,4,3/12,3,1
since b mentions that his eldest daughter has blue eyes and a immediately replies hence a has seen his eldest daughter perhaps 10 yrs ago hence answer is 12,3,1
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sir but the answer to the second part is 7/8 tan theta
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thanx to both biki & lone wolf i had done the same stps and arrived at the exact answer
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a hollow sphere is released from an inclined plane with a certain angle with respct to horizontal(assume any angle) find the coefficient of friction reqd to prevent slipping if the coefficient of friction is half the value found out, find the kinetic energy of the block as it slides a length l down the inclined plane
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hey anyone please help me with the problem 37 in hc verma pg 197. it is as follows the descending pulley shown in figure has a radius 20 cm and moment of inertia of 0.2 kg-m2. The fixed pulley is light and plane is frictionless. find the accelaration of the block if its mass is 1 kg . i am not able to get the exact answer.
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priyesh has explained really well
ur right
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exactly you get 38.333 m approx 33
bye!
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use the relative velocity concept
velocity of car 1 is 60x5/18=50/3 m/s
velocity of car 2 is 42x5/18=35/3 m/s
relative velocity of car1 with respect to car 2 is 50/3-35/3=15/3=5 m/s
car 1 has to travel a distance of 5+5 =10 m to overtake car2 (try to visualise)
hence time t to overtake car 2= 10/5 = 2 seconds
am solving for total distance
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When a body rolls on a horizontal rough surface will static frictional force act on the body?
Sliding friction will not act as the velocity of point of contact with respect to the ground is 0.is this also true?
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