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Catalogs Discussion Forums -> Organic Chemistry -> what are associated liquids -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
what are associated liquids
Catalogs Discussion Forums -> Physical Chemistry -> mvr = nh/2pi. What did Bohr prove/conclude by using this formula.Explanation needed. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
wel...he proved tha the valuet angular momentum for an electron(mvr) should be an integral multiple of that nh/2pi... where n is the principal quantum no.
Catalogs Discussion Forums -> Mechanics -> What is Mechanics -> Go to message
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A field of physics that studies the action of forces on objects made of matter.
Catalogs Discussion Forums -> Mechanics -> wht is friction -> Go to message
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The rubbing of one object or surface against another; Conflict, as between persons having dissimilar ideas or interests; clash; : A force that resists the relative motion or tendency to such motion of two bodies in contact...... (2) The rubbing of one object or surface against another; Conflict, as between persons having dissimilar ideas or interests; clash; : A force that resists the relative motion or tendency to such motion of two bodies in contac
Catalogs Discussion Forums -> Mechanics -> whts the relation between G and g -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]

 

 

this G is the gravitational constant and its value is 

 

 G = 6.67428 \times 10^{-11} \ \mbox{m}^3 \ \mbox{kg}^{-1} \ \mbox{s}^{-2} = 6.67428 \times 10^{-11} \ {\rm N}\, {\rm (m/kg)^2}

 

ang g is acceleration due to grvity and g= GM/R*R

Catalogs Discussion Forums -> General Physics -> What is Pulley -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
One of the simple machines; a wheel with a grooved rim in which a pulled rope or chain will lift an object (more useful when two or more pulleys are used together such that a small force moving through a greater distance can exert a larger force through a smaller distance)
Catalogs Discussion Forums -> Physical Chemistry -> water equivalent -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
if you could type the question fully i think its easy to answer...its like a gobbledegook
Catalogs Discussion Forums -> Physical Chemistry -> assertion: wen a sol of non volatile solute in volatile solvnt is distilld, boiling pt of da left ov -> Go to message
This Post 5 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]
well... its because as molality increases the moles of solute increases ...this is because Molality = Moles of solute divided by mass of solvent in kilogram..this increase causes the Vapour pressure to decrease..we know that boiling point is the temperature at which the vapour pressure is equal to the atmospheric pressure..thus only at higher temperature this happens which obviously causes the boiling poit to increase...
Catalogs Discussion Forums -> Physical Chemistry -> reference books for iit -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Physics- H.c. VERMAChemistry - NCERTMaths- TMH
Catalogs Discussion Forums -> Physical Chemistry -> what's the easy way to find the solubility of a compound -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]

 for a sparingly soluble salt the Ksp is derived by assuming a small amount will dissolve and yield ions according to its composition.The small amount that dissolves IS the actual solubility of the salt in moles/L.. soo since you have a value of 20 mg/L as the solubility of PbSO4 convert that to moles /L by dividing the grams of PbSO4/L
(20 mg/L = 0.02 grams/L ) by the molar mass of PbSO4 ( 207.2 + 32 + 64 = 303.2 grams/mole ) soo 0.02 grams /L / 303.2 grams/mol = 6.6 x 10^-5 moles/L = 6.6 X 10^-5 M as the actual solubility of PbSO4
Setting this in the Ksp relationship
Ksp( PbSO4) = [Pb+2][SO4^-2] a small amount of the insoluble salt ( 6.6 X 10^-5 M ) dissolved to yield 6.6 X 10^-5 M Pb+2 AND 6.6 X 10^-5 M SO4^-2 soo the Ksp = [6.6 x 10^-5][6.6 X 10^-5]
= 4.36 X 10^-9 ::::::.. using this Ksp one can determine what the solubility of PbSO4 is in a solution containing 0.01 M Na2SO4.

The .01 M Na2SO4 will ionize 100% to yield 2 x 0.01 M Na+ and 0.01M SO4^-2 soooooo the solubility of the PbSO4 ( x )is obtained by::
Ksp = 4.36 X 10^-9 = [Pb+2 = X ][total SO4^2 = X + 0.01 M ].
Because X is going to be very small compared to 0.01 neglect it in the 
X+ 0.01 M term and the equation reduces to:::: 0.01X =4.36 X 10^-9
solving for X ::: X = (4.36 X 10^-9)/10^-2:::::: X = 4.36 X 10^-7 M

so in the presence of 0.01 M SO4^-2 the solubility of PbSO4 is reduced from 6.6 X 10^-6 to 4.36 X 10^-7 or PbSO4 is 15 times less soluble in the presence of 0.01M SO4^-2

Catalogs Discussion Forums -> Physical Chemistry -> Is lowering of vapour pressure a colligative property? -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]

 actually colligative properties are studied for dilute solutions...

Catalogs Discussion Forums -> Physical Chemistry -> H(2)S atoxic gas with rotten egg like smell, is used for the qualitative analysis.If the solubility -> Go to message
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H(2)S atoxic gas with rotten egg like smell, is used for the qualitative analysis.If the solubility of H(2)S {hydrogen sulphide} in water at STP is 0.195m,calculate Henry's law constant.
Catalogs Discussion Forums -> Physical Chemistry -> Is lowering of vapour pressure a colligative property? -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
ya.. Lowering of vapour pressure is a colligative property (Roults law)
Catalogs Discussion Forums -> Lounge -> anybody appearing 4 physics olympiad??? if yes, what special preparation is required -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
yea ,, i am one of the cards appearing for physics olympiad...iwell if you are preparing for IIT-JEE that will do,,but a special preparation is needed for this and just try to solve as many problems you can from earlier question papers
Catalogs Discussion Forums -> General Physics -> i really don't practice physics coz m not able to do it' can two strong subjects help me in clearin -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
so,,just try to be strong in the lessons you like the most in physics and be strong with basic formulas .. i think that will do pal
Catalogs Discussion Forums -> General Physics -> i really don't practice physics coz m not able to do it' can two strong subjects help me in clearin -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
hi,k lets consider like this ... you cleared IIT -JEE without learning physics...k.. think what would happen if they call you for an oral interview ..i think they will surely consider your physics mark for consideration,
Catalogs Discussion Forums -> General Physics -> i really don't practice physics coz m not able to do it' can two strong subjects help me in clearin -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
HI ,, as per my knowledge two subjects cannot make you clear IIT-JEE ..
Catalogs Discussion Forums -> General Physics -> 1.Explain equilibrium of bodies!! 2.Give an example of motion of centre of mass 3.law of conservat -> Go to message
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Catalogs Discussion Forums -> General Physics -> 1.Explain equilibrium of bodies!! 2.Give an example of motion of centre of mass 3.law of conservat -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
help me out guys
Catalogs Discussion Forums -> General Physics -> 1.Explain equilibrium of bodies!! 2.Give an example of motion of centre of mass 3.law of conservat -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
1.Explain equilibrium of bodies!!2.Give an example of motion of centre of mass3.law of conservation of angular momentumplease guys help me out .u can also send mail @ snsankarnaren@gmail.com
 
 
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