see the angle bisector is the locus of a point which moves such that
it is always equidistant from the two given lines.....
let the point be P(h,k)
first making the c1 and c2(constant in given lines) of same sign
so eqn of angle bisector is
|(a1h+b1k+c1)/{root(a12+b1^2+)}| = +_ |(a2h+b2k+c2)/{root(a2^2+b2^2)}|...............(1)
now evaluate a1a2+b1b2(of changed eqn after making c1 and c22 of same sign)...........(2)
and also find (a1@+b1$+c1)(a2@+b2$+c2) .....................(3)
where (@,$)=(0,0) {origin}
if (a1@+b1$+c1)(a2@+b2$+c2)>0 then angle bisector with +ve sign(from 1 ) will contain the
point(origin in this case)
and if (a1@+b1$+c1)(a2@+b2$+c2)<0 then angle bisector with -ve sign(from 1) will contain the
point(origin).
now find a1a2+b1b2
if a1a2+b1b2>0 then angle bisector with positive sign will be obtuse angle bisector.
if a1a2+b1b2<0 then ....................".......... with -ve sign.........".........acute angle
bisector.
now to find whether acute angle bisector or obtuse angle bisector will contain the point
proceed like this
1)eqn 3 is +ve and eqn 2 is also +ve then obtuse angle bisector will contain the point(i.e. origin)
2)eqn 3 is +ve and eqn 2 is -ve then acute angle bisector will contain the point.
3)eqn3 is -ve and 2 is +ve then acute..........."..........................................
4)if 3 is -ve and 2 is -ve then obtuse ..................................."..........................