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Catalogs Discussion Forums -> Analytical Geometry -> Circle -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
where is the equation....?
Catalogs Discussion Forums -> Mechanics -> ) The greatest and least resultant of two forces acting on a body are 35 kN and 5 kN respectively. D -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]

 let the two forces be F1 and F2

so root(F1^2+F2^2+2F1F2cos@)=R.............................(1)

where @ is the angle b/w the two forces....

now u see resultant will be maximum when @=0 ( because cos0=1)

and resultant will be minimum when @=180 (because cos180=-1)

hence according to ur question from (1)

root(F1^2+F2^2+2F1F2cos0)=35KN

=> F1+F2=35........................(2)

and similarly F1-F2=5...........(3)....

u will get F1 and F2.....

and when resultant is 5KN then the angle b/w them will be 180 (coz 5KN is the least one)

hope i helped u 

Catalogs Discussion Forums -> Analytical Geometry -> Is x axis and y axis is perpendicular or not because we know condition of perpendicular is m1m2=-1 b -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]

 slope of x axis(m1)=-{1/slope of y axis(m2)}

                               =-(1/infinity)
                                =0... 
Catalogs Discussion Forums -> Differential Calculus -> discuss the differentiability of f(x)=x!x! at x=0. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
see at x=0 no sharp point is there .......the curve above x axis is for x^2 and curve below x axis is for -x^2....
Catalogs Discussion Forums -> Differential Calculus -> discuss the differentiability of f(x)=x!x! at x=0. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]

 

Catalogs Discussion Forums -> Differential Calculus -> discuss the differentiability of f(x)=x!x! at x=0. -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
see when x is positive then f(x)=x^2 ....and when x is negative then f(x)=-x^2....draw the graph of the function now......u can easily find that there is a continuous curve wid no any sharp point......it means that function is differentiable at x=0.....hope i helped u .....
Catalogs Discussion Forums -> Differential Calculus -> evaluate lim x tend to infinity 9x2+3x+7/5x2+2x+1 plz solve it -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
take x^2 as common from both num and den....and then put limits....u will get the answer as 9/5
Catalogs Discussion Forums -> Counselling Zone -> URGENT:MY AIEEE RANK IS 20174(AIR) AND 1098(STATE RANK ,M.P) -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
now he is in IIT
Catalogs Discussion Forums -> Counselling Zone -> how to study mechanics in civil engineering -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
Mechanics plays a very important role in Civil engineering. In first yr. the engg. mechanics is based on 12th level mechanics. But for further semesters.....u will read higher mechanics. So i m advising u to study it very well coz it is the back bone of civil engineering......
Catalogs Discussion Forums -> Lounge -> Make Friends -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
chinmay.saxena@gmail.com....
Catalogs Discussion Forums -> Analytical Geometry -> please suggest a good book for co-ordinate geometry theory to clear the concepts? -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
A Das gupta,arihant
Catalogs Discussion Forums -> Differential Calculus -> dy/dx=x+y+1/x+y -> Go to message
This Post 2 points    (Olaaa!! Perrrfect answer.   in 1 votes )   [?]

 put x+y=v

differentiate it wrt x

we get 1+dy/dx=dv/dx

now put it in ur question u will get 

dv/dx-1=(v+1)/v

dv/dx=(v+1)/v+1

now i think u can easily solve it

hope i helped u

Catalogs Discussion Forums -> Differential Calculus -> M really Weak At Limits, Derivatives And Continuity....plz tell me how to improve it -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
just do more and more practice....cuz practice makes a man perfect...
Catalogs Discussion Forums -> Lounge -> sachin ramesh tendulkar salute for u................ !!!! -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
and yeah Thanks to sachin,,,for such kind of batting ,,,and yeah salute to him,,,,,he is the best
Catalogs Discussion Forums -> Lounge -> sachin ramesh tendulkar salute for u................ !!!! -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
i was unlucky that i coudn't see this match live ,,,the reason is that i was just leaving Gwalior and at the same time sachin was moving to his new record......i saw his batting when i was on my way to station,,,i stopped to a showroom of Videocon TV and there i saw his 200......sachin ki 200 147 balls se pehle hi hojani chahiye thi,,,,but mujhe pura match dekhna hi pada and then suddenly i went for my train ,,,i was just lucky coz train had arrived to the station...... that experience was just awesome
Catalogs Discussion Forums -> Analytical Geometry -> Solve this:The area of the largest semicircle that can be drawn in an isosceles right triangle with -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]

2pie......

Catalogs Discussion Forums -> Lounge -> Let's begin this game... -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
I fell in love with a ninja Because someone offered me 1,000,000 dollars.
Catalogs Discussion Forums -> Analytical Geometry -> Find the equation of the bisector of the angle between 4x+y-7=0 and x-4y+3=0 which contains the o -> Go to message
This Post 12 points    (Olaaa!! Perrrfect answer.   in 3 votes )   [?]

 see the angle bisector is the locus of a point which moves such that

 

it is always equidistant from the two given lines.....

 

let the point be P(h,k)

 

first making the c1 and c2(constant in given lines) of same sign

 

so eqn of angle bisector is 

 

|(a1h+b1k+c1)/{root(a12+b1^2+)}| = +_ |(a2h+b2k+c2)/{root(a2^2+b2^2)}|...............(1)

 

now evaluate a1a2+b1b2(of changed eqn after making c1 and c22 of same sign)...........(2) 

 

and also find (a1@+b1$+c1)(a2@+b2$+c2) .....................(3)

 

where (@,$)=(0,0) {origin}

 

if (a1@+b1$+c1)(a2@+b2$+c2)>0 then angle bisector with +ve sign(from 1 ) will contain the

 

point(origin in this case)

 

and if (a1@+b1$+c1)(a2@+b2$+c2)<0 then angle bisector with -ve sign(from 1) will contain the

 

point(origin).

 

now  find a1a2+b1b2

 

if  a1a2+b1b2>0 then  angle bisector with positive sign will be obtuse angle bisector.

 

if a1a2+b1b2<0 then ....................".......... with -ve sign.........".........acute angle

 

bisector.

 

now to find whether acute angle bisector  or obtuse angle bisector will contain the point

 

proceed like this

 

1)eqn 3 is +ve and eqn 2 is also +ve then obtuse angle bisector will contain the point(i.e. origin)

 

2)eqn 3 is +ve and eqn 2 is -ve then acute angle bisector will contain the point.

 

3)eqn3 is -ve and 2 is +ve then acute..........."..........................................

 

4)if 3 is -ve and 2 is -ve then obtuse ..................................."..........................

 

Catalogs Discussion Forums -> Trignometry -> solve tan x + tan 2x + tan 3x -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
see question is not about the domain of given function.....in question there is an expresseion and u have to just simplify it and the result will also be an expression,,,,,,so u can solve by the method given by Sushobhan Sen
Catalogs Discussion Forums -> Lounge -> i want to know my death date -> Go to message
This Post 0 points    (Olaaa!! Perrrfect answer.   in 0 votes )   [?]
bhai jo bhi maroge jab bhi maroge 7 din main hi maroge,,,,8th din hota bhi hai kya???
 
 
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