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numericaly your ans is correct but i think that it should be with positive sign...
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let A bomb of mass m is thrown vertically in the air ... it explodes into two equal parts when its velocity is 21m/sec. If one part moves upto the height of 40m from the pt. of explosion then what is the position of second part fom pt. of explosion.
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As f=70v,
so retardation a=(f/m)v,
a=dv/dt
dv/dt=fv/m
integrate it with proper limits
you will find t=100log2/7sec
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As work done in close path is zero for conservative force.. so find close integeration of F.dr if it comes to zero then force is conservative
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Metthod given by elessar is correct but smaller angle angle b/w two vector is 45 .... you can checkit by shifting vectors parallely and join their tails.......
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If both rubber ball and metal ball hit the wall and bounce back then why change in momentum in rubber ball is more than change in momentum of metal ball.
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Right answer is train a will be accelerate pls give me the complete solution...... will rate you..
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Two identical trains a and b are moving with different velocities such that vel. of a is greater than vel. b. Now a packet is thrown out from train a to train b. and from b to a both packets have same mases. now which train will accelerate .
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