Messages posted by akku

thnx:):)

ethnx, bt its more imp 2 read it and ponder rather than comment:):)

People come into your life for a reason, a season or a lifetime. When you know which one it is, you will know what to do for that person.

When someone in your life for a REASON, it is usually to meet a need you have expressed. They have come to assist you through a difficulty, to provide you with guidance and support, to aid you physically, emotionally or spiritually. They may seem like godsend and they are.

They are there for the reason you need them to be. Then, without wrongdoing on your part or at an inconvenient time, these persons will say or do something to bring the relationship to an end.

Sometimes they die. Sometimes they walk away. Sometimes they act up and force you to take a stand. What we must realize is that our need has been met, out desire fulfilled, their wok is done. The prayer you sent up has been answered and knows it is time to move on-both for you and for them.

Some people come in your life for a SEASON, because your turn has come to share, grow or learn. They bring you an experience of peace or make u laugh.

They may teach you something you've never done. They usually give you an unbelievable amount of joy. Believe it; it is real, but only for a season.

LIFETIME relationships teach you lifetime lessons, things that you must build upon in order to have a solid emotional foundation. Your job is to accept the lesson, love the person and put what you have learned to use in all other relationship and areas of your life. It is said that love is blind but friendship is clairvoyant :):)

it was solved sme b4 , u may c this ::http://www.goiit.com/posts/list/electricity-capacitors-69378.htm#342476

taking 5^n outside

lim n---->inf 5(1+(4/5)^n)^1/n using the result lim n-->inf (k)^n=0 if 0<k <1

=5 ans

double post
c this:http://www.goiit.com/posts/list/differenciation-find-two-positive-nos-x-and-y-such-that-their-73494.htm

x2y5==x^2*y^5

am>=gm

(2*x/2+5*y/5)/7>=(x^2*y^5)^1/7

max(x^2y^5)=5^7

which occurs when x/2=y/5=k

x=2k,y=5k

7k=35

k=5

x=10,y=25 ans

DCE - Delhi College of Engineering had the following branch opening and closing ranks for AIEEE 2006. The branches are arranged in descening order of preference.

Branch Name State Category AIEEE Opening Rank AIEEE Closing Rank

Computer Engineering

OP 140 383

SC 4771 4771

ST 21510 21510

Electronics & Communication Engineering

OP 216 500

SC 4620 5067

ST 14859 14859

STPH 20080 20080

Information Technology

OP 508 983

OPPH 11406 11406

SC 12772 12772

ST 29005 29005

Mechanical Engineering

OP 626 1408

SC 9100 12103

ST 29785 29785

Electrical Engineering

OP 802 1373

SC 13262 17184

ST 20417 20417

Bio Technology

OP 1275 1692

SC 22820 22820

Production & Industrial Engineering

OP 1684 2955

SC 43331 43331

Civil Engineering

OP 2113 3267

OPPH 26341 26341

SC 23613 23613

ST 38833 38833

Polymer Science & Chemical Technology

OP 2142 4041

SC 37979 37979

Environmental Engineering

OP 4385 5297

6-7 hrs

very touching:):)

SRRY THERES AN ERROR-
NO OF SOLN ARE
6 AS RIGHTLY BY THE ABOVE USER

Product will be CH3CD(OH)C6H5

LiAlD4---->D^-1

(CH3CD(O^-1)C6H5)------>H30+------->CH3CD(OH)C6H5 ans

(d)12 is NOT the answer ans is (c)6

cos x=cosecy

-1<=cosx<=1 -1>=cosec y>=1

equality exists only when cosx=1,-1 and cosecy=1,-1

x=0,pi,2pi,3pi and y=pi/2,3pi/2,5pi/2

no of pairs(x,y)=3*4=12 WRONG anS

------------------------

SOLNS EXIST WEN cosx =1 and cosecy=1 ie x=0,2pi y=pi/2,5pi/2 =>4solns

and

wen

cosx =-1 and cosecy=-1 ie x=pi,3pi y=3pi/2 =>2 solns

in total 6 ans

its simple yaar
tan^3x=tanx*tan^2x=tanx(sec^2x-1)=tanxsec^2x-tanx
integrating
tan^2x/2-logsecx+C ans

its simple yaar
tan^3x=tanx*tan^2x=tanx(sec^2x-1)=tanxsec^2x-tanx
integrating
tan^2x/2-logsecx+C ans

Best is mesra

MESRA>PATNA>DEOGARH

1)put t=sin x , then solve
2)divide by cos^2x in num and den, use 1+tan^2x=sec^2x
t=tanx and solve

(x tan 2x - 2x tan x) / ((1-cos 2x)^2)

tan2x=2tanx/1-tan²x ; 1-cos2x=2sin²x ; x/sinx =1

2xtanx(1-1+tan²x)/1-tan²x *4sin⁴x

2x tan³x/(1-tan²x)*4sin⁴x= (x/sinx)*1/2*1/(1-tan²x)=1/2