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2.First take XY cordinate system and let assume particle starts its motion from the origin.
let displacement vector be d = xi + yj
Where x and y are net displacements along xaxis and y axis
From the given information x= 2+4=6 km , y=.5 km
now find magnitude and direction of d
Also first draw the diagram to understand it better..
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1. Acoording to the given information angle b/w two vectors A & B =110 - 20 = 90
So resultalt R = 3*3 +4*4 whole underoot
= 5
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Thanx Abhishek for solving the problem..........
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Which book is better for theory Haliday or University physics or any other book which you can suggest..
and what about feynman lactures in physics... also suggest books for specific topics
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solution provided by money seems to be correct but i want to know y mettal ball lose all its energy.......... because according to physics mettal ball is more elstic than rubber
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will a solid conductor and insulator hold same max. charge . Spheres are of the same radius give reasons please
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hey... its answer is 50m/sec let me know if i am correct i will tell u the sol....
here i take distance l=6km from pt. A..... am i right
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Good explanation elessar...........
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Heat flow as electromagnetic waves in vacuum like heat energy from sun i.e. infrared is a part of em spectrum..... it travels from sun to earth through space
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thanx everbody you all are right i will RATE YOU ALL
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ok... my doubt has cleared now.....
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ok u r correct....
but y not r we considering angle b/w p2 and -p1.....
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As we have to take change in vector so replace vector p1
with vector -p1 ....
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Answer provided by Joy is wrong....
As spheres r conc. therefore they must be hollow and for hollow sphere pot is constant and same as on the surface
Now find the pot. by each sphere and add them...
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When two waves of equal freq and amplitude travel in opp. direction then standing waves will produce so net transver of energy is zero.
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Lets take a small part of ring in the form of arc with length dl which suspends angle  on the centre of the ring.
Force b/w charge q and arc with charge=dq= (q/2 r)*dl, df= q*dq/r2
this force df=2*Tsin /2. As is very small so replace sin/2 to /2.
df= 2T/2
df=T (=dl/r)
T=df/
T=(q*q*dl*r)/dl*r*r*2r
T=q2/2pie*r*r
in above solution i have not taken dielectric constant ..... try to draw the diagram...
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