What will be the ratio of the area of two squares, one having its diagonal double than the other...
Suppose diagonals of 1st square = 2x
Suppose diagonal of 2nd square = 2x/2 = x
Area of 1st square =
Area of 2nd square
Their ratio = 2x2 : x2/2 = 4x2 : x2 = 4:1