see when a cyclist drive the bicycle and when he is not inclined then force of friction provides the centripetal force

now when motor cyclist is drving with a gr8 speed and when he bends that time the resultant vector R has two components R COS AND R SIN

HERE

R SIN =MV^2/r.................(1)

R COS =mg .................(2)

DIVIDE 1 &2

SO TAN =V^2/rg

SO WE GET V max =sqrt OF rg TAN

THIS IS THE MAX SPEED WITH WHICH A PERSON CAN DRIVE ON INCLINED PLANE AND SO THE CYCLIST IS NT THROWN OUT WHEN HE TAKES A TURN AND WHEN HE IS IN GR8 SPEED

HEY THE PERSON WHO ASKED THE QUESTION PLZ REPLY ME IF U SATISFIED AND CORRECT ME IF INCASE M WRONG

BEST OFF LUCK

while taking a turn two prominent forces act on the cyclist:one is the centripetal force towards the centre of rotation and the other is the frictional force which acts in the opposite direction..these two forcescreate a couple that tend to make the cyclist fall.thus he bends at an angle to the horizontal so as to keep himself on the bicycle.

tan =v^2/rg

@debotosh.babai

friction force is exerted by the ground on the bicycle.. which agent is responsible for the "centripetal force"?

when a cyclist takes the turn then frictional force start acting then this force provide necessary centripital force which is required to take the turn to take turn to he bends and he bend inwards

In this when  cyclist will take the turn then what will be the direction of normal reaction.

I mean will normal reaction be perpandicular to the surface or along the cycle...........i.e inclined.