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1 Dec 2007 06:40:48 IST
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Please solve HC verma problem 85 and 86.
My concepts on conservation of angular momentum are not very clear so plz give me some tips.......
86. Solid sphere is set into motion on a rough surface with linear velocity v collides elastically witha fixed smooth vertical wall. Find the speed of the sphere after it had started pure rolling in the backward direction.
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1 Dec 2007 21:05:26 IST
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hey anybody please solve this problem am waiting from last 14 hours....
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1 Dec 2007 21:16:57 IST
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hey buddy dont take it the other way but do u knw the answer key to HCV is available in marketss...they r of guud quality.....
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This problem has been solved a lot of times here on this forum. Anyway, let me do it again:
Now, consider the instant just after the ball collides with the wall.
Using conservation of momentum, mv + mv' = 0, or v' = -v, which implies the velocity of the ball immediately after collision is v'.
Conserving angular momentum about the point of contact:
-I = I'
Now, MI of the sphere about the bottom point = 2MR2/5 + MR2
[Icmw - mvr] = -Icmw' - mv'r [using v = rw]
=3/7mvr = 7/5mv'r
which gives v' = 3v/7.
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Will nip in at times to solve problems :)
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1 Dec 2007 22:13:50 IST
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Thanx Karthik...
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1 Dec 2007 22:16:53 IST
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Tell me if you have any doubts.
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Will nip in at times to solve problems :)
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