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2 Jun 2008 13:51:01 IST
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A RIVER IS FLOWING AT A SPEED OF 5 KM AND A MAN CAN SWIM AT THE SPEDD OF 4 KM AND HIS WAING SPEEDIS 1 FIND THE MINIMUM TIME TAEN TO REACH THE POINT DIRECTLY OPPOSITE TOP HIM ON THE OPP BANK AND ALSO FINDTHE DIRECTION TAKEN THE WIDTH OF THE RIVER 120 KM
WORKING SUPPOE HE MOVES AT AN ANGLE
@ TO THE PERPENDICULAR THE THE TIME TAKEN TO REACH WILL BE 120/4COS@
AMD THE DRIFT WILL BE (5-4COS@)120/4COS@
THE TIME TAKEN WILL BE (5-4COS@)120/4COS@/.1
SO TOTAL TIME =(5-4COS@)120/4COS@+120/4COS@
SO THE MINUMUM TIME WILL BE FOUND OUT BY TAKING ITS MINIMA WHICH I CANT
IF THERES A MISTAKE PLS VERIFY
IF NOT SOLVE IT
PLS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
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2 Jun 2008 14:01:57 IST
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unit of speed are wrong i guess it isKm/hr
i m not getting what is (WAING SPEEDIS 1) here
anyway the minimum time to reach opposite bank shouid be 30hours when he will swim along perpendicular to the river his actual velocity will be resultant of his own velocity and that of the river which can be easily calculated using pythagorus theorem bcoz vectors are perpendicular
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2 Jun 2008 14:05:56 IST
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His drift will be 150Km is he wish to cross river in minimum timr coz component of his velocity along river is 5Km/hr bcoz of river flowand time taken by him is 30hrs so his drift is 150Km
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2 Jun 2008 14:08:23 IST
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He can not cross the river without undergoing some drift bcoz for this his own speed(4km/hr) shouid be greater then velocity of river(5km/hr)
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3 Jun 2008 20:21:58 IST
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ACTUALLY EVERYTHING IT IS IN METRES AND SECONDS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
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4 Jun 2008 10:17:16 IST
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edit ur questn varun
it bcomin clumsy..
what is that 1 ??
km/ ??
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biki |
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4 Jun 2008 11:52:10 IST
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RIVER IS FLOWING AT A SPEED OF 5 m/s AND A MAN CAN SWIM AT THE SPEDD OF 4 m/s AND HIS WAlking SPEED IS 1 m/s FIND THE MINIMUM TIME TAEN TO REACH THE POINT DIRECTLY OPPOSITE TOP HIM ON THE OPP BANK AND ALSO FINDTHE DIRECTION TAKEN THE WIDTH OF THE RIVER 120 KM
WORKING SUPPOE HE MOVES AT AN ANGLE
@ TO THE PERPENDICULAR THE THE TIME TAKEN TO REACH WILL BE 120/4COS@
AMD THE DRIFT WILL BE (5-4COS@)120/4COS@
THE TIME TAKEN WILL BE (5-4COS@)120/4COS@/.1
SO TOTAL TIME =(5-4COS@)120/4COS@+120/4COS@
SO THE MINUMUM TIME WILL BE FOUND OUT BY TAKING ITS MINIMA WHICH I CANT
IF THERES A MISTAKE PLS VERIFY
IF NOT SOLVE IT
PLS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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4 Jun 2008 11:52:30 IST
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I HV EDITED IT
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
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5 Jun 2008 12:42:59 IST
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pls solve
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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5 Jun 2008 19:44:06 IST
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PLS SOLVE DUDES
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
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6 Jun 2008 12:36:34 IST
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VELO. OF RIVER (U)=5 M/S
VELO.OF MAN( V)= 4M/S
TAN =u/V
DRIFT(X)=(U/ V)* 120
X=150 m
TIME FOR WALKING-= 150s= t'
time for croosing river =120/ v*cos= t''
total time =t' +t''
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7 Jun 2008 07:18:57 IST
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ANTIDIXIT UR METHOD IS WRONG
ANYONE ELSE PLS
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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7 Jun 2008 08:13:38 IST
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I dont know if the solution below is correct.But i just gave a try.If it is wrong please say me in which part it's wrong.
Vinodh
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7 Jun 2008 11:48:48 IST
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ACTUALLLY WE HV TO FIND THE MIN TIME TAKEN SO WE HV TO USE DIFFRENTIATION
SEE
SUPPOSE THE SWIMMER MOVES AT AN @ WITH THE VERTICAL
THE LESSER @ WILL BE THE LESSER TIME WILL BE NEEDED TO REACH THE OPP SHORE BUT THE DRIFT WIL BE MORE
SO THE TIME TAKEN TO WALK WILL BE MORE SO THIS IS THE CONCEPT OF THIS PROBLEM
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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7 Jun 2008 12:00:07 IST
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In the previous post i have found the variable time as a fuction angle @ with vertical.Now differentiating might help.The remaining part is usual one.That's why i thought it might help.If there's any conceptual error plz notify me.
Vinodh
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8 Jun 2008 07:31:59 IST
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CAN U MAKE A FRESH DIAGRAM
I CANT UNDERSTAND PROPERLY
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From shadows a light shall spring
Renewed shall be blade that's broken
The crown less again shall be king.
MY BLOG
http://my.opera.com/vu2rje/blog/ |
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8 Jun 2008 19:54:17 IST
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I have read somewhere that in case the velocity of river is greater than the mans velocity then the direction of velocity of man with respecr to river is perpendicuar to the resultant velocity of man
in the figure
Vmr=velocity of man with respecr to river
Vmg=resultant velocity of man
vrg= velocity of river flow
this might help you.
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