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30 Jun 2007 12:13:11 IST
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If both rubber ball and metal ball hit the wall and bounce back then why change in momentum in rubber ball is more than change in momentum of metal ball.
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30 Jun 2007 12:19:34 IST
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Density of metal ball is greater. Hence for the same size, steel ball has more mass.
Hence more momentum change
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The rubber ball due to less rigidity than the metal ball,gets deformed at the instant of collision to a greater extent.
so the impulse that acts on the rubber ball during collision gets compensated in deforming the ball. so the rubber ball rebounds with a lesser velocity and thus lesser momentum. Thus the change in momentum of the rubber ball is more.
In the case of the metal ball,due to its rigidity,the deformation is very very less,so more of the impulse acts on it ,so it rebounds with a greater velocity(than the rubber ball).Thus the change of momentum is less.
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2 Jul 2007 20:57:09 IST
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him1808 has given a great explaination.
Good work him1808
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All men dream but not equally. Those who dream by night in the dusty recesses of their minds wake in the day to find that it was vanity; but the dreamers of the day are dangerous men, for they may act their dream with open eyes to make it possible. |
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3 Jul 2007 23:34:40 IST
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momentum of rubber ball is greater because change in momentum of the rubber ball is 2mv(final momenta-initial)elastic collison.in case of metal ball because,of its huge mass it losses all its energy in the form of heat when it hits the grounh(monentum is mv).this is the reason for ur question.
by
N.SURENDAR
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4 Jul 2007 11:43:58 IST
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solution provided by money seems to be correct but i want to know y mettal ball lose all its energy.......... because according to physics mettal ball is more elstic than rubber
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4 Jul 2007 17:06:58 IST
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there is a fine line when you talk about elasticity (E), elastic collision and coefficient of restitution (e). Of these only coefficient of restitution and elastic collission are completely related as. e=1 mean an elastic collission. However high elasticity means that the capability of a body to regain it shape after a load is applied. Higher load causing lesser deformation means higher elasticity. Which need not necessary mean higher value of e. e would depend on both the surfaces that are hitting each other.For example steel ball dropped on concrete might not rebound much but drop it on a steel surface and you will see a greater rebound. Hope that helps !
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4 Jul 2007 17:45:18 IST
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Indeed a perfect and fantastic explanation by abhishek. You deserve a salute man.
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A paradox is an argument that starts with apparently acceptable assumptions and leads by apparently valid deductions to an apparent contradiction. Since logic admits no contradictions, either the apparently acceptable assumptions are not acceptable, or the apparently valid
deductions are not valid, or the apparent contradiction is not a contradiction. A paradox moves us to reexamine the argument until we find out what is wrong.
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5 Jul 2007 10:54:41 IST
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Thanx Abhishek for solving the problem..........
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5 Jul 2007 14:02:09 IST
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velocity of a ball after bouncing is given by Vn=en . V where e=coeff. of elasticity n=no.of collisions v=intial vel. SO NOW e FOR RUBBER BALL N METAL BALL WILL BE DIFFERTENT SO VEL .S WILL BE DIFF. SO CHANGE IN MOMENTUM IS DIFF.
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5 Jul 2007 20:30:32 IST
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thanks for the compliment edison
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