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Ask community Community Discussion Question: WAVE optics YDSE
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A K (934)

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When white light instead of monochromatic light falls on a slit of YDSE
then one sees:
a  no interference
b  coloured fringes
c  black and white fringes
d  white central fringe with coloured fringes on either side
plzzz give the correct reason
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saurabh panda (236)

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actually shud be 'a' ,,,,
 
fringes ud be observed but it cant be very easily distinguished du to many freq. of light used....
and ya "b" is also possible...
coloured fringes will be observed
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A K (934)

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but ans given is d
this is a problem from D C Pandey Otptics and Modern Physics
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saurabh panda (236)

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arey quest. of white light never comes untill and unless white light is incident...
 
actually wat happens when white lit is incident is all the lights get into constituent colours but at centre
they recombine again to gve white light....
 
this cannot be observed in any other place normally bcos... they usuall attain a path diff. and cannot recombine prop. to gve white light...
 
thats why i sayed B option also.. and not last one
 
hope i m clear to ya
 
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A K (934)

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ya i do think the ans should be b
anyway thanx
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saurabh panda (236)

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oh!!!!!!!!!!
me stupid....
i do make same mistakes not readin question completely.......
 
yaar its given white light.....
 
ans. is D for sure must be....
 
and ya a can also be a side ans. for multiple choice
 
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A K (934)

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plzzz explain the reason
D C PANDEY HAS given in pg 129 that only coloured fringes are formed
and the answer says something else
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A K (934)

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how is the recombination of constituent colours related to interference
??
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Madmax (1732)

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Coloured fringes will be produced everywhere else except for the central fringe which is white Due to various levels of Constructive and destructive interference

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saurabh panda (236)

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do u realise y diff. colours are obtained?
 
its bcos they hve diff. wavelenghth...
and thus diff. path diff everytime..
 
now why at centre white light is formed is gven by me earliear...
anyways
actually wat happens when white lit is incident is all the lights get into constituent colours but at centre
they recombine again to gve white light....
 
this cannot be observed in any other place normally bcos... they usuall attain a path diff. and cannot recombine prop. to gve white light...
 
now that shud be clear...
and srry 4 earlier silly mistake
Cheers !!!!!!!
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A K (934)

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so finally answer should be D right???/
then it means that the theory point given in pg 129 is wrong
wanted this confirmation
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A K (934)

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yes agree wid ur reason madmax
and shubham ur reason too
so finally is the ans D
right????
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saurabh panda (236)

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arey no... (yes ans is D)
its absolutely correct here
 
see. recombination means they hve constructve interference..
 
specially here they reach a state where they were b4 ...rit while in white light...
 
no path diff.. as if they didnt diffract at all......
 
understand now...... colours r formed as said but they dun alays interfere in perfect manner to give white light
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Madmax (1732)

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The violet end of the spectrum (with the shortest wavelengths) is closer to the central WHITE fringe, with the other colours being further away in order.

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A K (934)

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yes thanx again
thanx to all
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Madmax (1732)

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Dude One more thing tht i just read Online


You can actually do the single slit experiment wherever you are right now! Hold two of your fingers very close together; there should be only the tiniest little gap between them that you can barely see through. Look towards a light source, light a light bulb, through the gap in your fingers. In the gap between your fingers you shold see very faint gray lines that run parallel to your fingers... these are the destructive interference "dark" fringes!

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saurabh panda (236)

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see dude anader one is fairly very simple exp...
 
see this
 
see ur finger nails closely and carefully in light... what do u see..
u will see light and dark bands near each other very close as stripes..
this is due to interfernce only..
 
hope u will fnd this interestin..
this i read somewhere in a gud book and u can easily observe it....
it happens only at closely spaced areas of finger nails
 
Cheers!!!!!!
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Swashata Ghosh (519)

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RefQ.When white light instead of monochromatic light falls on a slit of YDSE
then one sees:
a  no interference
b  coloured fringes
c  black and white fringes
d  white central fringe with coloured fringes on either side


Ans.......________
Hi Buddy m giving u the correct answer...
U r right the correct option is "d"

The explanation is as follows....

    The interference patterns due to different componenet colours of white light overlap incoherently. The central bright fringes for all the different colours are at the same position. So the central fringe is white. Since blue colour(neglecting violate) has the minimum wave length, the fringe closest on either side of the central white fringe is blue. After a few fringes, no clear fringe pattern is seen.

Hence the correct option is
d. white central fringe with coloured fringes on either side

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