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27 Feb 2008 18:06:40 IST
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When white light instead of monochromatic light falls on a slit of YDSE then one sees: a no interference b coloured fringes c black and white fringes d white central fringe with coloured fringes on either side plzzz give the correct reason rates assured
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27 Feb 2008 18:28:11 IST
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actually shud be 'a' ,,,, fringes ud be observed but it cant be very easily distinguished du to many freq. of light used.... and ya "b" is also possible... coloured fringes will be observed
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27 Feb 2008 18:32:01 IST
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but ans given is d this is a problem from D C Pandey Otptics and Modern Physics
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27 Feb 2008 18:40:37 IST
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arey quest. of white light never comes untill and unless white light is incident... actually wat happens when white lit is incident is all the lights get into constituent colours but at centre they recombine again to gve white light.... this cannot be observed in any other place normally bcos... they usuall attain a path diff. and cannot recombine prop. to gve white light... thats why i sayed B option also.. and not last one hope i m clear to ya Cheers!!!!!!!
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27 Feb 2008 18:42:02 IST
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ya i do think the ans should be b anyway thanx
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27 Feb 2008 18:44:17 IST
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oh!!!!!!!!!! me stupid....  i do make same mistakes not readin question completely....... yaar its given white light..... ans. is D for sure must be.... and ya a can also be a side ans. for multiple choice
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27 Feb 2008 18:45:06 IST
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plzzz explain the reason D C PANDEY HAS given in pg 129 that only coloured fringes are formed and the answer says something else
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27 Feb 2008 18:48:17 IST
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how is the recombination of constituent colours related to interference ??
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27 Feb 2008 18:49:53 IST
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Coloured fringes will be produced everywhere else except for the central fringe which is white Due to various levels of Constructive and destructive interference
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27 Feb 2008 18:50:16 IST
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do u realise y diff. colours are obtained? its bcos they hve diff. wavelenghth... and thus diff. path diff everytime.. now why at centre white light is formed is gven by me earliear... anyways actually wat happens when white lit is incident is all the lights get into constituent colours but at centre they recombine again to gve white light.... this cannot be observed in any other place normally bcos... they usuall attain a path diff. and cannot recombine prop. to gve white light... now that shud be clear... and srry 4 earlier silly mistake Cheers !!!!!!!
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27 Feb 2008 18:52:03 IST
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so finally answer should be D right???/ then it means that the theory point given in pg 129 is wrong wanted this confirmation
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27 Feb 2008 18:52:40 IST
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yes agree wid ur reason madmax and shubham ur reason too so finally is the ans D right????
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27 Feb 2008 18:55:44 IST
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arey no... (yes ans is D) its absolutely correct here see. recombination means they hve constructve interference.. specially here they reach a state where they were b4 ...rit while in white light... no path diff.. as if they didnt diffract at all...... understand now...... colours r formed as said but they dun alays interfere in perfect manner to give white light
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27 Feb 2008 18:57:10 IST
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The violet end of the spectrum (with the shortest wavelengths) is closer to the central WHITE fringe, with the other colours being further away in order.
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------------------------ MY SIGGIE -------------------------
Cansomeonepleasetellmethelocationofthespacebar ?
« ¤ º NoRmaL PeOplE ScAre Me º ¤ »
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27 Feb 2008 18:57:15 IST
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yes thanx again thanx to all
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27 Feb 2008 18:59:24 IST
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Dude One more thing tht i just read Online
You can actually do the single slit experiment wherever you are right now! Hold two of your fingers very close together; there should be only the tiniest little gap between them that you can barely see through. Look towards a light source, light a light bulb, through the gap in your fingers. In the gap between your fingers you shold see very faint gray lines that run parallel to your fingers... these are the destructive interference "dark" fringes!
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------------------------ MY SIGGIE -------------------------
Cansomeonepleasetellmethelocationofthespacebar ?
« ¤ º NoRmaL PeOplE ScAre Me º ¤ »
http://lifeofnavin.blogspot.com
(The place to be at!!)
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27 Feb 2008 19:08:06 IST
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see dude anader one is fairly very simple exp... see this see ur finger nails closely and carefully in light... what do u see.. u will see light and dark bands near each other very close as stripes.. this is due to interfernce only.. hope u will fnd this interestin.. this i read somewhere in a gud book and u can easily observe it.... it happens only at closely spaced areas of finger nails Cheers!!!!!!
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1 Mar 2008 18:12:08 IST
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RefQ.When white light instead of monochromatic light falls on a slit of YDSE then one sees: a no interference b coloured fringes c black and white fringes d white central fringe with coloured fringes on either side
Ans.......________ Hi Buddy m giving u the correct answer... U r right the correct option is "d"
The explanation is as follows....
The interference patterns due to different componenet colours of white light overlap incoherently. The central bright fringes for all the different colours are at the same position. So the central fringe is white. Since blue colour(neglecting violate) has the minimum wave length, the fringe closest on either side of the central white fringe is blue. After a few fringes, no clear fringe pattern is seen.
Hence the correct option is d. white central fringe with coloured fringes on either side
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