If you assume the dipole is short then to ignore the dimension of the dipole the condition is that the dimension of sphere( radius in this case) should be >> length of the dipole.
But here nothing is mentioned as far as the dimensions of sphere and dipole is concerned. Thus your assumption holds no ground.
Moreover when dipole is enclosed in the sphere
The total charge enclosed by the sphere = 0
Hence by gauss's law of electrostatics the flux = q / ebsylum = 0
so statement (A) is valid
Also the distribution of charge is not symmetric w.r.t sphere so
(C) electric field is not zero anywhere on the sphere.