The answer for this according to the book is 0. Please post solution.

look, it's easy :

first when x tends from positive side to zero.

greatest integer of cosx will result in zero =>sin0 =0 absolutely,

now for negative side,

as cos is positive in first and 4th quad.

and it's value is always less than 1,

so, it again results in zero when greatest integer is applied to it.

So, everytime your numerator is ablsolutely, Sin0, means 0.

Hence, the ans.

Hope you got it now. :)

Dude may I point out that when the value is negative and tends to zero, then the greatest integer funtion value is -1 AND NOT ZERO.

dude!! what i am trying to make u understand that,

cos(-x) = Cos x.

Do u remember that?

First think of it.

So, cos x where x is approaching from negative side results in cos x

see, you can see it from graph of cosx, what value it attains from +0 as well as -0.

u'll find it's just near to 1 and not 1.

clear now?

please read the last post first.
I have told that graph of cosx approaches 1 for both +0 and -0.
But it's greatest integer is always 0.
Because it's never exactly 1.
That's what i have written.
Hope it's clear now. :)

please read the last post first.
I have told that graph of cosx approaches 1 for both +0 and -0.
But it's greatest integer is always 0.
Because it's never exactly 1.
That's what i have written.
Hope it's clear now. :)