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Reply Forum Index -> Differential Calculus originally posted here on IIT-JEE / AIEEE community   
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babu (0)

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BY PARTS THEORM
    
Chima (0)

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It is quite simple, its just uv-? v dv, where you have to pick (u) and v is the intregal of the other part. For example (?x^2sinxdx) u=x^2 and v=? of sinx which is of course -cosx. plug it in and you'll have your answer :)
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Chima (0)

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sorry ? was suppose to be the intergal

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Vishal Mahuli (55)

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The integral of product of 2 functions is equal to the difference betn the product of first function n derivative second function and the intergral of product of integral of second function and derivative of the first function..

(first func multipied by integral of second) ---- [INTEGRAL of (integral  of second func multiplied by derivative of the first)]

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