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9 Sep 2011 14:11:12 IST
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(x-2)^2+(y-2)^2=1 ....find the maximum value of y/x??
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9 Sep 2011 14:55:57 IST
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is the answer 16+2 (55)^.5/6if yes then take y=mx and find condition of tangency.As Radius=perp. Dist. Of centre from tangent M is equal to y/x
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10 Sep 2011 09:29:10 IST
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tan ( pi/4 + cot^-1 ( sqrt (7) ) )
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22 Sep 2011 17:28:49 IST
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make function in x and find dy/dx
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