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Ask community Community Discussion Question: circular permutation
Reply Forum Index -> Algebra originally posted here on IIT-JEE / AIEEE community   
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vijay kharya (514)

Olaaa!! Perrrfect answer. 86  [128 rates]

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If n distinct objects are arranged in a circle then the number of ways of selecting 3 of these things so that no 2 of them are next to each other is

 

A. ( n(n-4)(n-6) )/12

 

b. ( n(n-4)(n-5) )/6

 

C. ( n(n-3)(n-4) )/6

 

D.  ( n(n-4)(n-6) )/4


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never say never (33)

Olaaa!! Perrrfect answer. 3  [12 rates]

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 kya ans  option 3 hai mera pura nahi ayya but ifyou can select the first things in n way the you can select thenext thing in (n-3) ways but

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vijay kharya (514)

Olaaa!! Perrrfect answer. 86  [128 rates]

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sorry friend but your answer is wrong. please can someone explain the answer. it is given as option b
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